# pdfutils.py - everything to do with images, streams,
# compression, and some constants
from __future__ import print_function
import os
from io import StringIO
from rdkit.six import string_types
import glob

LINEEND = '\015\012'


##########################################################
#
#  image compression helpers.  Preprocessing a directory
#  of images will offer a vast speedup.
#
##########################################################
def cacheImageFile(filename):
  "Processes the image as if for encoding, saves to a file ending in AHX"
  from PIL import Image
  import zlib
  img1 = Image.open(filename)
  img = img1.convert('RGB')
  imgwidth, imgheight = img.size
  code = []
  code.append('BI')  # begin image
  # this describes what is in the image itself
  code.append('/W %s /H %s /BPC 8 /CS /RGB /F [/A85 /Fl]' % (imgwidth, imgheight))
  code.append('ID')
  #use a flate filter and Ascii Base 85
  raw = getattr(img, 'tobytes', img.tostring)()
  assert len(raw) == imgwidth * imgheight, "Wrong amount of data for image"

  compressed = zlib.compress(raw)  #this bit is very fast...
  encoded = _AsciiBase85Encode(compressed)  #...sadly this isn't

  #write in blocks of 60 characters per line
  outstream = StringIO(encoded)
  dataline = outstream.read(60)
  while dataline != "":
    code.append(dataline)
    dataline = outstream.read(60)

  code.append('EI')

  #save it to a file
  cachedname = os.path.splitext(filename)[0] + '.a85'
  f = open(cachedname, 'wb')
  f.write(LINEEND.join(code) + LINEEND)
  f.close()
  print('cached image as %s' % cachedname)


def preProcessImages(spec):
  """accepts either a filespec ('C:\mydir\*.jpg') or a list
    of image filenames, crunches them all to save time.  Run this
    to save huge amounts of time when repeatedly building image
    documents."""
  if isinstance(spec, string_types):
    filelist = glob.glob(spec)
  else:  #list or tuple OK
    filelist = spec

  for filename in filelist:
    if cachedImageExists(filename):
      print('cached version of %s already exists' % filename)
    else:
      cacheImageFile(filename)


def cachedImageExists(filename):
  """Determines if a cached image exists which has
    the same name and equal or newer date to the given
    file."""
  cachedname = os.path.splitext(filename)[0] + '.a85'
  if os.path.isfile(cachedname):
    #see if it is newer
    original_date = os.stat(filename)[8]
    cached_date = os.stat(cachedname)[8]
    if original_date > cached_date:
      return 0
    else:
      return 1
  else:
    return 0


##############################################################
#
#            PDF Helper functions
#
##############################################################
def _escape(s):
  """PDF escapes are almost like Python ones, but brackets
    need slashes before them too. Use Python's repr function
    and chop off the quotes first"""
  s = repr(s)[1:-1]
  s = s.replace('(', '\(')
  s = s.replace(')', '\)')
  return s


def _normalizeLineEnds(text, desired=LINEEND):
  """ensures all instances of CR, LF and CRLF end up as the specified one"""
  unlikely = '\000\001\002\003'
  text = text.replace('\015\012', unlikely)
  text = text.replace('\015', unlikely)
  text = text.replace('\012', unlikely)
  text = text.replace(unlikely, desired)
  return text


def _AsciiHexEncode(input):
  """This is a verbose encoding used for binary data within
    a PDF file.  One byte binary becomes two bytes of ASCII."""
  "Helper function used by images"
  output = StringIO()
  for char in input:
    output.write('%02x' % ord(char))
  output.write('>')
  output.reset()
  return output.read()


def _AsciiHexDecode(input):
  "Not used except to provide a test of the preceding"
  #strip out all whitespace
  stripped = ''.join(input.split(), '')
  assert stripped[-1] == '>', 'Invalid terminator for Ascii Hex Stream'
  stripped = stripped[:-1]  #chop off terminator
  assert len(stripped) % 2 == 0, 'Ascii Hex stream has odd number of bytes'
  i = 0
  output = StringIO()
  while i < len(stripped):
    twobytes = stripped[i:i + 2]
    output.write(chr(eval('0x' + twobytes)))
    i = i + 2
  output.reset()
  return output.read()


def _AsciiHexTest(text='What is the average velocity of a sparrow?'):
  "Do the obvious test for whether Ascii Hex encoding works"
  print('Plain text:', text)
  encoded = _AsciiHexEncode(text)
  print('Encoded:', encoded)
  decoded = _AsciiHexDecode(encoded)
  print('Decoded:', decoded)
  if decoded == text:
    print('Passed')
  else:
    print('Failed!')


def _AsciiBase85Encode(input):
  """This is a compact encoding used for binary data within
    a PDF file.  Four bytes of binary data become five bytes of
    ASCII.  This is the default method used for encoding images."""
  outstream = StringIO()
  # special rules apply if not a multiple of four bytes.
  whole_word_count, remainder_size = divmod(len(input), 4)
  cut = 4 * whole_word_count
  body, lastbit = input[0:cut], input[cut:]

  for i in range(whole_word_count):
    offset = i * 4
    b1 = ord(body[offset])
    b2 = ord(body[offset + 1])
    b3 = ord(body[offset + 2])
    b4 = ord(body[offset + 3])

    num = 16777216 * b1 + 65536 * b2 + 256 * b3 + b4

    if num == 0:
      #special case
      outstream.write('z')
    else:
      #solve for five base-85 numbers
      temp, c5 = divmod(num, 85)
      temp, c4 = divmod(temp, 85)
      temp, c3 = divmod(temp, 85)
      c1, c2 = divmod(temp, 85)
      assert ((85**4) * c1) + ((85**3) * c2) + ((85**2) * c3) + (85 * c4) + c5 == num, 'dodgy code!'
      outstream.write(chr(c1 + 33))
      outstream.write(chr(c2 + 33))
      outstream.write(chr(c3 + 33))
      outstream.write(chr(c4 + 33))
      outstream.write(chr(c5 + 33))

  # now we do the final bit at the end.  I repeated this separately as
  # the loop above is the time-critical part of a script, whereas this
  # happens only once at the end.

  #encode however many bytes we have as usual
  if remainder_size > 0:
    while len(lastbit) < 4:
      lastbit = lastbit + '\000'
    b1 = ord(lastbit[0])
    b2 = ord(lastbit[1])
    b3 = ord(lastbit[2])
    b4 = ord(lastbit[3])

    num = 16777216 * b1 + 65536 * b2 + 256 * b3 + b4

    #solve for c1..c5
    temp, c5 = divmod(num, 85)
    temp, c4 = divmod(temp, 85)
    temp, c3 = divmod(temp, 85)
    c1, c2 = divmod(temp, 85)

    #print 'encoding: %d %d %d %d -> %d -> %d %d %d %d %d' % (
    #    b1,b2,b3,b4,num,c1,c2,c3,c4,c5)
    lastword = chr(c1 + 33) + chr(c2 + 33) + chr(c3 + 33) + chr(c4 + 33) + chr(c5 + 33)
    #write out most of the bytes.
    outstream.write(lastword[0:remainder_size + 1])

  #terminator code for ascii 85
  outstream.write('~>')
  outstream.reset()
  return outstream.read()


def _AsciiBase85Decode(input):
  """This is not used - Acrobat Reader decodes for you - but a round
    trip is essential for testing."""
  outstream = StringIO()
  #strip all whitespace
  stripped = ''.join(input.split(), '')
  #check end
  assert stripped[-2:] == '~>', 'Invalid terminator for Ascii Base 85 Stream'
  stripped = stripped[:-2]  #chop off terminator

  #may have 'z' in it which complicates matters - expand them
  stripped = stripped.replace('z', '!!!!!')
  # special rules apply if not a multiple of five bytes.
  whole_word_count, remainder_size = divmod(len(stripped), 5)
  #print '%d words, %d leftover' % (whole_word_count, remainder_size)
  assert remainder_size != 1, 'invalid Ascii 85 stream!'
  cut = 5 * whole_word_count
  body, lastbit = stripped[0:cut], stripped[cut:]

  for i in range(whole_word_count):
    offset = i * 5
    c1 = ord(body[offset]) - 33
    c2 = ord(body[offset + 1]) - 33
    c3 = ord(body[offset + 2]) - 33
    c4 = ord(body[offset + 3]) - 33
    c5 = ord(body[offset + 4]) - 33

    num = ((85**4) * c1) + ((85**3) * c2) + ((85**2) * c3) + (85 * c4) + c5

    temp, b4 = divmod(num, 256)
    temp, b3 = divmod(temp, 256)
    b1, b2 = divmod(temp, 256)

    assert num == 16777216 * b1 + 65536 * b2 + 256 * b3 + b4, 'dodgy code!'
    outstream.write(chr(b1))
    outstream.write(chr(b2))
    outstream.write(chr(b3))
    outstream.write(chr(b4))

  #decode however many bytes we have as usual
  if remainder_size > 0:
    while len(lastbit) < 5:
      lastbit = lastbit + '!'
    c1 = ord(lastbit[0]) - 33
    c2 = ord(lastbit[1]) - 33
    c3 = ord(lastbit[2]) - 33
    c4 = ord(lastbit[3]) - 33
    c5 = ord(lastbit[4]) - 33
    num = ((85**4) * c1) + ((85**3) * c2) + ((85**2) * c3) + (85 * c4) + c5
    temp, b4 = divmod(num, 256)
    temp, b3 = divmod(temp, 256)
    b1, b2 = divmod(temp, 256)
    assert num == 16777216 * b1 + 65536 * b2 + 256 * b3 + b4, 'dodgy code!'
    #print 'decoding: %d %d %d %d %d -> %d -> %d %d %d %d' % (
    #    c1,c2,c3,c4,c5,num,b1,b2,b3,b4)

    #the last character needs 1 adding; the encoding loses
    #data by rounding the number to x bytes, and when
    #divided repeatedly we get one less
    if remainder_size == 2:
      lastword = chr(b1 + 1)
    elif remainder_size == 3:
      lastword = chr(b1) + chr(b2 + 1)
    elif remainder_size == 4:
      lastword = chr(b1) + chr(b2) + chr(b3 + 1)
    outstream.write(lastword)

  #terminator code for ascii 85
  outstream.reset()
  return outstream.read()


def _wrap(input, columns=60):
  output = []
  length = len(input)
  i = 0
  pos = columns * i
  while pos < length:
    output.append(input[pos:pos + columns])
    i = i + 1
    pos = columns * i

  return LINEEND.join(output)


def _AsciiBase85Test(text='What is the average velocity of a sparrow?'):
  "Do the obvious test for whether Base 85 encoding works"
  print('Plain text:', text)
  encoded = _AsciiBase85Encode(text)
  print('Encoded:', encoded)
  decoded = _AsciiBase85Decode(encoded)
  print('Decoded:', decoded)
  if decoded == text:
    print('Passed')
  else:
    print('Failed!')
