str_nth_number_after_mth {strex}R Documentation

Find the nth number after the mth occurrence of a pattern.

Description

Given a string, a pattern and natural numbers n and m, find the nth number after the mth occurrence of the pattern.

Usage

str_nth_number_after_mth(
  string,
  pattern,
  n,
  m,
  decimals = FALSE,
  leading_decimals = decimals,
  negs = FALSE,
  sci = FALSE,
  commas = FALSE,
  leave_as_string = FALSE
)

str_nth_number_after_first(
  string,
  pattern,
  n,
  decimals = FALSE,
  leading_decimals = decimals,
  negs = FALSE,
  sci = FALSE,
  commas = FALSE,
  leave_as_string = FALSE
)

str_nth_number_after_last(
  string,
  pattern,
  n,
  decimals = FALSE,
  leading_decimals = decimals,
  negs = FALSE,
  sci = FALSE,
  commas = FALSE,
  leave_as_string = FALSE
)

str_first_number_after_mth(
  string,
  pattern,
  m,
  decimals = FALSE,
  leading_decimals = decimals,
  negs = FALSE,
  sci = FALSE,
  commas = FALSE,
  leave_as_string = FALSE
)

str_last_number_after_mth(
  string,
  pattern,
  m,
  decimals = FALSE,
  leading_decimals = decimals,
  negs = FALSE,
  sci = FALSE,
  commas = FALSE,
  leave_as_string = FALSE
)

str_first_number_after_first(
  string,
  pattern,
  decimals = FALSE,
  leading_decimals = decimals,
  negs = FALSE,
  sci = FALSE,
  commas = FALSE,
  leave_as_string = FALSE
)

str_first_number_after_last(
  string,
  pattern,
  decimals = FALSE,
  leading_decimals = decimals,
  negs = FALSE,
  sci = FALSE,
  commas = FALSE,
  leave_as_string = FALSE
)

str_last_number_after_first(
  string,
  pattern,
  decimals = FALSE,
  leading_decimals = decimals,
  negs = FALSE,
  sci = FALSE,
  commas = FALSE,
  leave_as_string = FALSE
)

str_last_number_after_last(
  string,
  pattern,
  decimals = FALSE,
  leading_decimals = decimals,
  negs = FALSE,
  sci = FALSE,
  commas = FALSE,
  leave_as_string = FALSE
)

Arguments

string

A character vector.

pattern

The pattern to look for.

The default interpretation is a regular expression, as described in stringi::about_search_regex.

To match a without regular expression (i.e. as a human would), use coll(). For details see stringr::regex().

n, m

Vectors of integerish values. Must be either length 1 or have length equal to the length of string. Negative indices count from the back: while 1 and 2 correspond to first and second, -1 and -2 correspond to last and second-last. 0 will return NA.

decimals

Do you want to include the possibility of decimal numbers (TRUE) or not (FALSE, the default).

leading_decimals

Do you want to allow a leading decimal point to be the start of a number?

negs

Do you want to allow negative numbers? Note that double negatives are not handled here (see the examples).

sci

Make the search aware of scientific notation e.g. 2e3 is the same as 2000.

commas

Allow comma separators in numbers (i.e. interpret 1,100 as a single number (one thousand one hundred) rather than two numbers (one and one hundred)).

leave_as_string

Do you want to return the number as a string (TRUE) or as numeric (FALSE, the default)?

Value

A numeric or character vector.

See Also

Other numeric extractors: str_extract_numbers(), str_nth_number_before_mth(), str_nth_number()

Examples

string <- c(
  "abc1abc2abc3abc4abc5abc6abc7abc8abc9",
  "abc1def2ghi3abc4def5ghi6abc7def8ghi9"
)
str_nth_number_after_mth(string, "abc", 1, 3)
str_nth_number_after_mth(string, "abc", 2, 3)
str_nth_number_after_first(string, "abc", 2)
str_nth_number_after_last(string, "abc", -1)
str_first_number_after_mth(string, "abc", 2)
str_last_number_after_mth(string, "abc", 1)
str_first_number_after_first(string, "abc")
str_first_number_after_last(string, "abc")
str_last_number_after_first(string, "abc")
str_last_number_after_last(string, "abc")
[Package strex version 1.4.2 Index]