R: does a vector have the sum required to be a row or column of...

is.ok {magic} | R Documentation

## does a vector have the sum required to be a row or column of a magic square?

### Description

Returns `TRUE` if and only if `sum(vec)==magic.constant(n,d=d))`

### Usage

    is.ok(vec, n=length(vec), d=2)

### Arguments

`vec` | Vector to be tested
`n` | Order of square or hypercube. Default assumes order is equal to length of `vec`
`d` | Dimension of square or hypercube. Default of 2 corresponds to a square

### Author(s)

Robin K. S. Hankin

### Examples

     is.ok(magic(5)[1,])

[Package magic version 1.5-6 Index]