| branches_attr_by_labels {dendextend} | R Documentation |
The user supplies a dend, labels, and type of condition (all/any), and TF_values And the function returns a dendrogram with branches col/lwd/lty accordingly
branches_attr_by_labels(dend, labels, TF_values = c(2, Inf), attr = c("col",
"lwd", "lty"), type = c("all", "any"), ...)
dend |
a dendrogram dend |
labels |
a character vector of labels from the tree |
TF_values |
a two dimensional vector with the TF_values to use in case a branch fulfills the condition (TRUE) and in the case that it does not (FALSE). Defaults are 2/Inf for col, lwd and lty. (so it will insert the first value, and will not change all the FALSE cases) |
attr |
a character with one of the following values: col/lwd/lty |
type |
a character vector of either "all" or "any", indicating which of the branches should be painted: ones that all of their labels belong to the supplied labels, or also ones that even some of their labels are included in the labels vector. |
... |
ignored. |
A dendrogram with modified branches (col/lwd/lty).
noded_with_condition, get_leaves_attr, nnodes, nleaves
## Not run:
library(dendextend)
set.seed(23235)
ss <- sample(1:150, 10 )
# Getting the dend dend
dend <- iris[ss,-5] %>% dist %>% hclust %>% as.dendrogram
dend %>% plot
dend %>%
branches_attr_by_labels(c("123", "126", "23", "29")) %>%
plot
dend %>%
branches_attr_by_labels(c("123", "126", "23", "29"), "all") %>%
plot # the same as above
dend %>%
branches_attr_by_labels(c("123", "126", "23", "29"), "any") %>%
plot
dend %>%
branches_attr_by_labels(c("123", "126", "23", "29"),
"any", "col", c("blue", "red")) %>% plot
dend %>%
branches_attr_by_labels(c("123", "126", "23", "29"),
"any", "lwd", c(4,1)) %>% plot
dend %>%
branches_attr_by_labels(c("123", "126", "23", "29"),
"any", "lty", c(2,1)) %>% plot
## End(Not run)